This lesson introduces the feedback-system concepts behind the Nyquist stability criterion and explains how a Nyquist plot represents a system’s frequency response.
A feedback control system combines a forward-path transfer function G(s) with a feedback-path transfer function H(s). For negative feedback, the closed-loop transfer function is
The product G(s)H(s) is the open-loop transfer function (OLTF). In a unity-feedback system, H(s)=1, so the denominator that determines the closed-loop poles is 1+G(s). More generally, the characteristic equation is 1+G(s)H(s)=0.
All flashcards
Open-loop transfer function
The product of the forward-path and feedback-path transfer functions, G(s)H(s).
Negative-feedback closed-loop transfer function
T(s)=1+G(s)H(s)G(s).
Nyquist plot
A complex-plane trace of the open-loop frequency response as frequency varies.
Critical point for unity negative feedback
−1, where the characteristic denominator 1+G(s)H(s) becomes zero.
Nyquist method advantage
It can assess closed-loop stability from open-loop frequency response without explicitly solving for every closed-loop pole.
Quiz questions
With clockwise encirclements counted as positive, what relation does the argument principle give for a mapped contour around the origin?Answer: N=Z−P, where Z and P count enclosed zeros and poles.
A negative-feedback system has P=2 open-loop right-half-plane poles. What net encirclement count is required for closed-loop stability, using clockwise encirclements as positive?Answer: Two net counterclockwise encirclements of −1, so N=−2.
What should be done when an open-loop pole lies on the imaginary axis during Nyquist analysis?Answer: Indent the contour around the pole and include the mapped indentation in the curve.
Which system type is not covered by the basic Nyquist criterion as a general stability test?Answer: Nonlinear systems, which require suitable nonlinear analysis methods.
What does a Nyquist curve passing exactly through −1 indicate for unity negative feedback?Answer: The characteristic equation has a root on the imaginary-axis boundary.