CalculusLesson 3 of 3 in the course Techniques of integration

Trigonometric, Half-Angle, and Hyperbolic Substitutions

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

Trigonometric substitution turns a radical expression into a simpler trigonometric expression. This lesson introduces the method and applies it to radicals involving a2−x2a^2-x^2.

For a>0a>0, set x=asin⁡θx=a\sin\theta. Then dx=acos⁡θ dθdx=a\cos\theta\,d\theta and

a2−x2=a2(1−sin⁡2θ)=acos⁡θ,\sqrt{a^2-x^2}=\sqrt{a^2(1-\sin^2\theta)}=a\cos\theta,

provided θ\theta is restricted to −π/2≤θ≤π/2-\pi/2\leq\theta\leq\pi/2, where cos⁡θ≥0\cos\theta\geq0.

All flashcards

Which radical form is commonly simplified by setting x=asin⁡θx=a\sin\theta?
A radical containing a2−x2a^2-x^2, especially a2−x2\sqrt{a^2-x^2}.
What is the differential when x=asin⁡θx=a\sin\theta?
Differentiating gives dx=acos⁡θ dθdx=a\cos\theta\,d\theta.
How does x=asin⁡θx=a\sin\theta simplify a2−x2\sqrt{a^2-x^2}?
It gives acos⁡θa\cos\theta on the principal arcsine range when a>0a>0.
What is an antiderivative of 1/a2−x21/\sqrt{a^2-x^2}?
arcsin⁡(x/a)+C\arcsin(x/a)+C, for a>0a>0 and ∣x∣<a|x|<a.
How are bounds converted under x=asin⁡θx=a\sin\theta?
Use θ=arcsin⁡(x/a)\theta=\arcsin(x/a) with angles in [−π/2,π/2][-\pi/2,\pi/2].

Quiz questions

  1. Which substitution is standard for an integrand containing a2−x2\sqrt{a^2-x^2}, with a>0a>0?Answer: x=asin⁡θx=a\sin\theta
  2. Which identity simplifies 1−sin⁡2θ1-\sin^2\theta?Answer: 1−sin⁡2θ=cos⁡2θ1-\sin^2\theta=\cos^2\theta
  3. If x=asin⁡θx=a\sin\theta, what is dxdx?Answer: dx=acos⁡θ dθdx=a\cos\theta\,d\theta
  4. Why is −π/2≤θ≤π/2-\pi/2\leq\theta\leq\pi/2 useful when simplifying a2−x2\sqrt{a^2-x^2} after x=asin⁡θx=a\sin\theta?Answer: Cosine is nonnegative, so cos⁡2θ=cos⁡θ\sqrt{\cos^2\theta}=\cos\theta.
  5. Under x=asin⁡θx=a\sin\theta, what are the transformed bounds when xx goes from 00 to a/2a/2, for a>0a>0?Answer: θ\theta goes from 00 to π/6\pi/6.

Based on the Wikipedia article Trigonometric substitution, licensed CC BY-SA 4.0. Adapted into a summary, flashcards and quizzes.

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