CalculusLesson 1 of 4 in the course Sequences and series

Geometric Series: Finite Sums, Convergence, and Applications

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

This lesson introduces geometric sequences and the series formed by adding their terms. These ideas help describe repeated multiplication, steady growth, and repeated shrinkage.

A geometric sequence is formed by multiplying each term by the same fixed number to obtain the next term. That fixed number is the common ratio, usually written as rr. If the first term is aa, the terms are a,ar,ar2,ar3,…a, ar, ar^2, ar^3,\ldots. The term at index kk, starting with index 0, is arkar^k.

All flashcards

What is the finite sum of a geometric series with initial term aa, ratio r≠1r\ne1, and indices 00 through nn?
Sn=a(1−rn+1)1−rS_n=\frac{a(1-r^{n+1})}{1-r}.
What is the finite geometric sum when r=1r=1?
Every term equals aa, so Sn=a(n+1)S_n=a(n+1).
What is the error after summing a convergent geometric series through index nn?
S−Sn=arn+11−rS-S_n=\frac{ar^{n+1}}{1-r}.
How is a geometric series related to a power series?
It is a power series with the same coefficient at every power.
What is the present value of end-of-year payments PP made forever with discount factor dd, where 0<d<10<d<1?
P1−d\frac{P}{1-d}.

Quiz questions

  1. For initial term aa, ratio r≠1r\ne1, and terms indexed from 00 through nn, which formula gives the finite geometric sum?Answer: Sn=a(1−rn+1)1−rS_n=\frac{a(1-r^{n+1})}{1-r}
  2. A finite geometric sum has initial term aa, ratio r=1r=1, and indices 00 through nn. What is its sum?Answer: a(n+1)a(n+1)
  3. What is the sum of the infinite geometric series 34+316+364+⋯\frac{3}{4}+\frac{3}{16}+\frac{3}{64}+\cdots?Answer: 11
  4. For a convergent geometric series with initial term aa and ratio rr, what is the signed difference S−SnS-S_n after summing through index nn?Answer: arn+11−r\frac{ar^{n+1}}{1-r}
  5. A payment PP is made at the end of each year forever, with discount factor dd per year and 0<d<10<d<1. What is its present value?Answer: P1−d\frac{P}{1-d}

Based on the Wikipedia article Geometric series, licensed CC BY-SA 4.0. Adapted into a summary, flashcards and quizzes.

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