Differential equationsLesson 1 of 2 in the course First-order ordinary differential equations

Separation of Variables Across ODEs, Heat PDEs, and Eigenfunction Methods

5 flashcards · 5 quiz questions · 5 match pairs · 4 fill-in sentences · English

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Summary

A first-order ODE is separable when it can be written as

This arrangement is called separation of variables. The differential notation is a convenient way to display the substitution used when integrating; it should not be taken as permission to manipulate every derivative like an ordinary fraction without regard to the equation.

∫1h(y) dy=∫g(x) dx+C.\int \frac{1}{h(y)}\,dy=\int g(x)\,dx+C.

All flashcards

How can a first-order ODE be recognized as separable?
Its right-hand side factors as g(x)h(y)g(x)h(y), so the variables can be separated before integration.
How does the substitution z=y(n−1)z=y^{(n-1)} help with some higher-order ODEs?
For y(n)=f(y(n−1))g(x)y^{(n)}=f(y^{(n-1)})g(x), it gives the separable first-order equation z′=f(z)g(x)z'=f(z)g(x).
What role do boundary conditions play in separated heat-equation solutions?
They select the permissible spatial eigenvalues and eigenfunctions.
What ODE describes each mode of a forced one-dimensional heat equation?
For mode nn, it is un′+αn2π2L2un=hn(t)u_n'+\alpha\frac{n^2\pi^2}{L^2}u_n=h_n(t).
What is a Kronecker sum of two matrices?
For matrices AA and BB, it is A⊗I+I⊗BA\otimes I+I\otimes B, with identity matrices of appropriate sizes.

Quiz questions

  1. For an ODE of the form y(n)=f(y(n−1))g(x)y^{(n)}=f(y^{(n-1)})g(x), what equation results from setting z=y(n−1)z=y^{(n-1)}?Answer: z′=f(z)g(x)z'=f(z)g(x), a first-order separable equation.
  2. For the heat equation ut=αuxxu_t=\alpha u_{xx} on 0≤x≤L0\le x\le L with u(0,t)=u(L,t)=0u(0,t)=u(L,t)=0, which eigenvalues allow nontrivial spatial modes?Answer: λn=n2π2L2\lambda_n=\frac{n^2\pi^2}{L^2} for n=1,2,3,…n=1,2,3,\ldots
  3. For the sine-series expansion of initial data f(x)f(x) on [0,L][0,L], what is the coefficient of sin⁡(nπx/L)\sin(n\pi x/L)?Answer: Dn=2L∫0Lf(x)sin⁡(nπxL) dxD_n=\frac{2}{L}\int_0^L f(x)\sin\left(\frac{n\pi x}{L}\right)\,dx
  4. For a forced heat equation with zero endpoint conditions, which equation governs mode nn?Answer: un′(t)+αn2π2L2un(t)=hn(t)u_n'(t)+\alpha\frac{n^2\pi^2}{L^2}u_n(t)=h_n(t)
  5. How is a two-dimensional discrete Laplacian assembled from one-dimensional operators DxxD_{xx} and DyyD_{yy}?Answer: Dxx⊗I+I⊗DyyD_{xx}\otimes I+I\otimes D_{yy}

Based on the Wikipedia article Separation of variables, licensed CC BY-SA 4.0. Adapted into a summary, flashcards and quizzes.

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