General physicsLesson 1 of 3 in the course Oscillatory Motion and Waves

Hooke’s Law, Damping, and Elastic Potential Energy

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

An object at rest remains at rest unless acted on by a net force. Likewise, an object moving at constant velocity continues in a straight line unless a force changes its motion. An object that oscillates must therefore experience forces that change its motion.

Imagine pulling a flexible ruler sideways and releasing it. Bending the ruler deforms it, and the ruler exerts a force back toward its stable, undeformed position. This is a restoring force. As the ruler moves back through equilibrium, it has momentum, so it continues past equilibrium and bends in the opposite direction. The restoring force then points back the other way, and the cycle repeats.

All flashcards

Restoring force
A force directed toward equilibrium that opposes the displacement of a system.
Hooke’s law
The relationship F=−kxF=-kx, where the restoring force is proportional to displacement and points in the opposite direction.
Force constant
The quantity kk that measures stiffness; a larger value means more force is needed for the same displacement.
Damping
The reduction in oscillation amplitude as dissipative forces transfer mechanical energy to other forms.
Elastic potential energy
Energy stored in a deformed system that can exert a restoring force.

Quiz questions

  1. On a graph of applied force against displacement during gradual spring stretching, what does the work correspond to?Answer: The area beneath the force-versus-displacement curve.
  2. What is the elastic potential energy of a Hooke’s-law system displaced by xx?Answer: PEel=12kx2PE_{el}=\frac{1}{2}kx^2.
  3. Why does the work required to stretch a Hooke’s-law spring gradually from equilibrium include a factor of 12\frac{1}{2}?Answer: The applied force rises uniformly from zero to its final value, so its average is half that value.
  4. If all the stored spring energy becomes a projectile’s kinetic energy, which equation relates the energy to projectile speed?Answer: PEel=12mv2PE_{el}=\frac{1}{2}mv^2.
  5. Why does a real toy gun generally transfer less spring energy to a projectile than an idealized model predicts?Answer: Friction, sound, and other losses divert some energy from the projectile.

Based on College Physics 2e by Paul Peter Urone, Roger Hinrichs (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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