OpticsLesson 2 of 2 in the course Geometric Optics and Image Formation

Simple Magnifiers: Angular Magnification and Viewing Arrangements

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

This lesson explains why an object can appear larger when it subtends a larger angle at the eye, and how a convex lens can create an enlarged view. These ideas are the foundation for understanding magnifying glasses.

The eye forms an image on the retina. For objects of the same physical size, the one that subtends a larger angle at the eye forms a larger retinal image and therefore appears larger.

All flashcards

What is a simple magnifier?
A converging lens used with an object inside its focal length to produce an enlarged, upright, virtual image.
What does it mean for an image to be virtual?
The light rays do not meet at the image location; they only appear to come from there.
How is angular magnification defined?
It is the ratio of the image's angular size to the unaided object's angular size: M=θimage/θobjectM = \theta_{\text{image}}/\theta_{\text{object}}.
What is the general angular-magnification equation for a virtual-image viewing arrangement?
M=(25 cm/L)(1+(L−ℓ)/f)M = (25\,\text{cm}/L)\left(1 + (L - \ell)/f\right), with LL, ℓ\ell, and ff expressed in centimeters.
How does a magnifier's focal length affect its angular magnification?
For the stated viewing arrangements, a shorter focal length produces greater angular magnification.

Quiz questions

  1. For a virtual-image viewing arrangement, which expression gives angular magnification when LL, ℓ\ell, and ff are in centimeters?Answer: M=(25 cm/L)(1+(L−ℓ)/f)M = (25\,\text{cm}/L)\left(1 + (L - \ell)/f\right)
  2. A magnifier with focal length 5.0 cm5.0\,\text{cm} is held close to the eye, with the virtual image at the 25 cm25\,\text{cm} near point. What is its angular magnification?Answer: 6.06.0
  3. For a simple magnifier whose virtual image is at infinity, what is the angular magnification?Answer: M=25 cm/fM = 25\,\text{cm}/f
  4. In the described geometry, the eye is a distance ℓ\ell from the lens and the virtual image is a distance LL from the eye. Under the usual thin-lens sign convention, what is the relation between image distance did_i and these distances?Answer: −di=L−ℓ-d_i = L - \ell
  5. For near-point viewing with the magnifier close to the eye, what happens to angular magnification when the lens's focal length is shortened?Answer: It increases.

Based on University Physics Volume 3 by Samuel J. Ling, Jeff Sanny, William Moebs (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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