ProbabilityLesson 1 of 1 in the course Discrete Random Variables

Geometric Distributions: Counting Conventions and Waiting-Time Formulas

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

A geometric distribution models repeated attempts when we are waiting for the first success. This lesson introduces the experiment’s defining conditions and explains why independence, constant probabilities, and the meaning of the random variable matter.

A geometric experiment consists of independent trials repeated until the first success occurs. Each trial has one of two outcomes: success or failure.

All flashcards

What is the probability that the first success occurs on trial xx when XX counts trials through success?
P(X=x)=(1−p)x−1pP(X=x)=(1-p)^{x-1}p for x=1,2,3,…x=1,2,3,\ldots.
How are the trial-count variable XX and failure-count variable YY related?
X=Y+1X=Y+1, because XX includes the successful trial and YY counts only earlier failures.
What are the mean and standard deviation of the number of trials through the first success?
μX=1/p\mu_X=1/p and σX=1−p/p\sigma_X=\sqrt{1-p}/p.
What is the common ratio of successive point probabilities in a geometric trial-count distribution?
1−p1-p; each next point probability is the previous one multiplied by 1−p1-p.
What does the memoryless property say about a geometric waiting time?
Earlier failures do not change the distribution of the remaining wait for success.

Quiz questions

  1. If XX counts trials through the first success, what is P(X=x)P(X=x) for x≥1x\geq 1?Answer: (1−p)x−1p(1-p)^{x-1}p
  2. For a geometric variable XX counting trials through the first success, what is its expected value?Answer: 1/p1/p
  3. Which equation expresses memorylessness for a trial-count geometric variable, for integers n≥1n\geq1 and k≥0k\geq0?Answer: P(X>k+n∣X>k)=P(X>n)P(X>k+n\mid X>k)=P(X>n)
  4. For XX counting trials through the first success, what is the ratio P(X=x+1)/P(X=x)P(X=x+1)/P(X=x)?Answer: 1−p1-p
  5. If YY counts failures before the first success, which probability formula applies for y≥0y\geq0?Answer: P(Y=y)=(1−p)ypP(Y=y)=(1-p)^y p

Based on Introductory Statistics 2e by Barbara Illowsky, Susan Dean (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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