ThermodynamicsLesson 4 of 4 in the course The Second Law of Thermodynamics

Microscopic Entropy, Entropy Changes, and the Third Law

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

Lesson progress
0 / 5

Your progress is kept in this browser only.Sign up to save it

Summary

This lesson connects entropy with the microscopic arrangements of particles and explains how that perspective helps us understand the second law of thermodynamics.

Entropy can be understood statistically by considering how many microscopic arrangements, or microstates, are consistent with a system’s observable condition. A system has higher entropy when its particles can be arranged in more possible ways.

All flashcards

Microstate
A specific microscopic arrangement of a system’s particles that is consistent with its observable state.
Entropy as a state function
Entropy change depends only on the initial and final states, not on the process path.
Entropy change at constant specific heat
For mass mm and constant specific heat cc, heating from TAT_A to TBT_B gives ΔS=mcln⁡(TB/TA)\Delta S=mc\ln(T_B/T_A), with temperatures in kelvins.
Entropy change in ideal-gas free expansion
For an ideal gas expanding from V1V_1 to V2V_2, ΔS=nRln⁡(V2/V1)\Delta S=nR\ln(V_2/V_1).
Third law of thermodynamics
Absolute zero cannot be reached through any finite number of cooling steps.

Quiz questions

  1. For an irreversible thermodynamic process, what happens to the entropy of the universe?Answer: It increases overall, even if one part becomes more ordered.
  2. Why can a reversible path be used to calculate entropy change for an irreversible process?Answer: Entropy change depends on the initial and final states, not the path.
  3. During melting at a fixed temperature, how is a substance’s entropy change calculated?Answer: Divide the heat transferred reversibly by the absolute temperature.
  4. What does the third law state about reaching absolute zero?Answer: It cannot be reached through any finite number of cooling steps.
  5. An ideal gas expands freely from volume V1V_1 to V2V_2. What is its entropy change?Answer: nRln⁡(V2/V1)nR\ln(V_2/V_1)

Based on University Physics Volume 2 by Samuel J. Ling, William Moebs, Jeff Sanny (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

All Thermodynamics lessons