General chemistryLesson 1 of 3 in the course Acid-Base Equilibria

pH and pOH: Logarithms, Temperature, and Applications

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

pH and pOH are logarithmic ways to describe the concentrations of hydronium and hydroxide ions in aqueous solutions. They make it easier to compare concentrations that may differ by many orders of magnitude.

The terms acidic and basic describe the relative concentrations of the two ions. A neutral solution does not mean the ions are absent; it means their concentrations are equal.

All flashcards

What does it mean for a solution to be neutral?
A neutral solution has equal concentrations of hydronium and hydroxide ions: [H3O+]=[OH−][\mathrm{H_3O^+}]=[\mathrm{OH^-}].
How are pH and hydronium concentration related?
pH is the negative base-10 logarithm of hydronium molarity: pH=−log⁡[H3O+]\mathrm{pH}=-\log[\mathrm{H_3O^+}].
What does pOH measure?
pOH expresses hydroxide ion molarity on a logarithmic scale: pOH=−log⁡[OH−]\mathrm{pOH}=-\log[\mathrm{OH^-}].
What is the pH–pOH relationship at 25 °C?
At 25 °C, pH+pOH=14.00\mathrm{pH}+\mathrm{pOH}=14.00, because pKw=14.00\mathrm{p}K_w=14.00.
Why can neutral water have a pH other than 7?
The value of KwK_w varies with temperature. Neutrality requires equal hydronium and hydroxide concentrations, but those equal concentrations—and therefore the pH—can change with temperature.

Quiz questions

  1. How is an acidic aqueous solution identified by comparing its hydronium and hydroxide concentrations?Answer: [H3O+]>[OH−][\mathrm{H_3O^+}]>[\mathrm{OH^-}]
  2. What is the definition of pH?Answer: pH=−log⁡[H3O+]\mathrm{pH}=-\log[\mathrm{H_3O^+}]
  3. At 25 °C, what is the sum of pH and pOH?Answer: 14.00
  4. At 25 °C, a solution has a pH of 4. Which classification is correct?Answer: Acidic
  5. Pure water at 80 °C has equal hydronium and hydroxide concentrations and a pH of 6.31. What does this indicate?Answer: It is neutral because equal ion concentrations define neutrality at that temperature.

Based on Chemistry 2e by Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson, PhD (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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