General chemistryLesson 1 of 6 in the course Liquids and Solids

Intermolecular Forces, Molecular Shape, and Their Effects on Matter

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

This lesson introduces how particles behave in solids, liquids, and gases, and how attractions between particles help explain the properties of each phase.

A particle means an atom, molecule, or ion. Particles in a solid are tightly packed, often in a regular arrangement, and vibrate around fixed positions. In a liquid, particles remain close together but are not arranged regularly; they move past one another while staying in contact. In a gas, particles are far apart, move independently, and interact mainly during collisions.

All flashcards

London dispersion force
An attraction caused by temporary dipoles that induce dipoles in neighboring particles; it occurs in all atoms and molecules.
Polarizability
How readily a particle’s electron cloud can be distorted; larger particles are generally more polarizable.
Permanent molecular dipole
A separation of partial positive and partial negative charge within a polar molecule.
Why can branching lower the boiling point of similar nonpolar molecules?
Branching can make molecules more compact, reducing intermolecular contact and weakening dispersion attractions.
How do hydrogen bonds help DNA strands remain separable?
Many hydrogen bonds stabilize base pairs, while their relative weakness allows the strands to unzip when needed.

Quiz questions

  1. Which particles experience London dispersion forces?Answer: All atoms and molecules, whether polar or nonpolar.
  2. Why does n-pentane boil at a higher temperature than neopentane?Answer: Its elongated shape allows greater intermolecular contact and stronger dispersion attractions.
  3. What attraction occurs between the partially positive end of one polar molecule and the partially negative end of another?Answer: A dipole-dipole attraction.
  4. How many hydrogen bonds are shared by a cytosine–guanine base pair in DNA?Answer: Three hydrogen bonds.
  5. For one mole of HCl, which process requires much more energy: vaporization or breaking the H–Cl covalent bonds?Answer: Breaking the H–Cl covalent bonds, which requires about 430 kJ per mole.

Based on Chemistry 2e by Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson, PhD (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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