General chemistryLesson 6 of 6 in the course Essential Ideas

Dimensional Analysis, Unit Conversions, and Temperature Scales

5 flashcards · 5 quiz questions · 5 match pairs · 4 fill-in sentences · English

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Summary

Many useful quantities cannot be measured directly. Instead, we measure related properties and calculate the quantity we need. This lesson introduces dimensional analysis, a method for organizing calculations by applying the same operations to numbers and units.

speed=distancetime\text{speed}=\frac{\text{distance}}{\text{time}}

100 m10 s=10 m/s\frac{100\,\text{m}}{10\,\text{s}}=10\,\text{m/s}

All flashcards

Derived quantity
A quantity calculated from other quantities using a mathematical relationship.
Dimensional analysis
A calculation method that applies the same operations to units as to numbers.
Conversion factor
A ratio of equivalent quantities in different units that has a value of one.
Density
Mass divided by volume.
Absolute temperature scale
A scale whose zero point is absolute zero; kelvin is such a scale.

Quiz questions

  1. Given 1 oz=28.349 g1\,\text{oz}=28.349\,\text{g}, which factor converts a mass in grams to ounces?Answer: 1 oz28.349 g\frac{1\,\text{oz}}{28.349\,\text{g}}
  2. Which relationship defines density?Answer: Mass divided by volume.
  3. What is the Fahrenheit temperature corresponding to 37.0 ∘C37.0\,^{\circ}\text{C}?Answer: 98.6 ∘F98.6\,^{\circ}\text{F}
  4. What is 2.00 L2.00\,\text{L} expressed in milliliters?Answer: 2.00×103 mL2.00\times10^3\,\text{mL}
  5. What is the kelvin temperature equivalent to 25.00 ∘C25.00\,^{\circ}\text{C}?Answer: 298.15 K298.15\,\text{K}

Based on Chemistry 2e by Paul Flowers, Klaus Theopold, Richard Langley, William R. Robinson, PhD (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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