Differential equationsLesson 1 of 4 in the course Higher-order linear equations

Characteristic Equations: Roots and Solutions of Linear Differential Equations

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

Lesson progress
0 / 5

Your progress is kept in this browser only.Sign up to save it

Summary

The characteristic equation turns a suitable differential equation into an algebraic equation. Solving this polynomial gives values that can be used to build the differential equation’s general solution.

A characteristic equation can be formed for a linear, homogeneous differential equation with constant coefficients, such as

any(n)+an−1y(n−1)+⋯+a1y′+a0y=0.a_n y^{(n)}+a_{n-1}y^{(n-1)}+\cdots+a_1y'+a_0y=0.

All flashcards

What is a characteristic equation?
An algebraic equation whose roots help construct solutions of suitable constant-coefficient differential or difference equations.
What does homogeneous mean for a differential equation?
The right-hand side is zero, as in any(n)+⋯+a0y=0a_n y^{(n)}+\cdots+a_0y=0.
Why is y=erxy=e^{rx} useful as a trial function?
Its jjth derivative is rjerxr^j e^{rx}, so substitution reduces the differential equation to a polynomial in rr.
What is the characteristic equation for any(n)+⋯+a0y=0a_n y^{(n)}+\cdots+a_0y=0?
anrn+an−1rn−1+⋯+a1r+a0=0a_n r^n+a_{n-1}r^{n-1}+\cdots+a_1r+a_0=0.
What trial sequence is used for a constant-coefficient recurrence?
Try yt=rty_t=r^t and substitute it into the recurrence to obtain its characteristic equation.

Quiz questions

  1. A constant-coefficient differential equation has distinct real characteristic roots r1,…,rnr_1,\ldots,r_n. Which form gives its general solution?Answer: y(x)=∑j=1ncjerjxy(x)=\sum_{j=1}^{n}c_j e^{r_jx}
  2. A real characteristic root rr has multiplicity kk. What form does its contribution to the general solution take?Answer: erxe^{rx} multiplied by a polynomial of degree at most k−1k-1
  3. For real coefficients, what real-valued solution contribution comes from a complex-root pair a±bia\pm bi, with b≠0b\ne0?Answer: eax(C1cos⁡bx+C2sin⁡bx)e^{ax}(C_1\cos bx+C_2\sin bx)
  4. For a constant-coefficient difference equation, what root condition gives stability in the criterion described?Answer: Every characteristic root has modulus less than 11.
  5. For a time-dependent, constant-coefficient linear differential equation, what root condition gives stability in the criterion described?Answer: Every characteristic root has a negative real part.

Based on the Wikipedia article Characteristic equation (calculus), licensed CC BY-SA 4.0. Adapted into a summary, flashcards and quizzes.

All Differential equations lessons