General physicsLesson 4 of 4 in the course Oscillatory Motion and Waves

Energy Conservation and Maximum Speed in Oscillators

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

This lesson introduces the forms of mechanical energy in an ideal simple harmonic oscillator and explains how energy shifts between them during motion. Understanding this exchange helps explain why an oscillator speeds up and slows down as it moves.

A spring stores elastic potential energy when it is displaced from equilibrium. For a spring with force constant kk and displacement xx from equilibrium, this energy is

All flashcards

How does amplitude affect a spring oscillator’s maximum speed?
For fixed mass and spring stiffness, maximum speed is proportional to amplitude: vmax⁡=Xk/mv_{\max}=X\sqrt{k/m}.
What is a spring oscillator’s speed at displacement xx?
For amplitude XX, v=±k/mX2−x2v=\pm\sqrt{k/m}\sqrt{X^2-x^2}; the sign indicates direction.
What is the maximum tangential speed of a small-angle pendulum?
For length LL and angular amplitude θmax⁡\theta_{\max} in radians, vmax⁡=gL θmax⁡v_{\max}=\sqrt{gL}\,\theta_{\max}.
What is the amplitude of an oscillator?
The magnitude of its greatest displacement from equilibrium.
How does a small-angle pendulum’s energy change during a swing?
Gravitational potential energy decreases toward the lowest point as kinetic energy increases.

Quiz questions

  1. A spring oscillator has amplitude XX and is at displacement xx. Which expression gives its instantaneous velocity?Answer: v=±k/mX2−x2v=\pm\sqrt{k/m}\sqrt{X^2-x^2}
  2. What is the maximum speed of a mass mm oscillating on a spring of stiffness kk with amplitude XX?Answer: vmax⁡=Xk/mv_{\max}=X\sqrt{k/m}
  3. For a small-angle pendulum of length LL and maximum angular displacement θmax⁡\theta_{\max}, what is its maximum angular speed?Answer: ωmax⁡=g/L θmax⁡\omega_{\max}=\sqrt{g/L}\,\theta_{\max}
  4. If an oscillator’s displacement is y(t)=asin⁡(ωt)y(t)=a\sin(\omega t), which expression gives its velocity?Answer: v(t)=aωcos⁡(ωt)v(t)=a\omega\cos(\omega t)
  5. How are angular frequency ω\omega and period TT related?Answer: ω=2π/T\omega=2\pi/T

Based on College Physics 2e by Paul Peter Urone, Roger Hinrichs (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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