General physicsLesson 5 of 8 in the course Kinematics

One-Dimensional Constant-Acceleration Kinematics: Equations and Problem Solving

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

Lesson progress
0 / 5

Your progress is kept in this browser only.Sign up to save it

Summary

This lesson establishes the notation and assumptions used throughout one-dimensional constant-acceleration problems. It also shows how average velocity relates to displacement when motion is uniform or when acceleration is constant.

We choose the initial time to be zero, so elapsed time is simply tt. A subscript 00 marks an initial value; a quantity without a subscript is a final value.

All flashcards

What does the subscript 00 indicate in kinematics?
It marks an initial value, such as initial position x0x_0 or initial velocity v0v_0.
How is displacement defined?
Displacement is the change in position: Δx=x−x0\Delta x=x-x_0; it is not necessarily total distance traveled.
How is average velocity calculated under constant acceleration?
It is the arithmetic mean of initial and final velocity: vˉ=v0+v2\bar{v}=\frac{v_0+v}{2}.
What equation gives final position from average velocity?
x=x0+vˉtx=x_0+\bar{v}t.
When is the time-independent velocity equation useful?
When time is not given or needed: v2=v02+2a(x−x0)v^2=v_0^2+2a(x-x_0).

Quiz questions

  1. An object moves in the negative direction, and its acceleration is also negative. Assuming the acceleration continues, what happens to its speed?Answer: Its speed increases.
  2. Which equation relates final velocity, initial velocity, acceleration, and displacement without using time?Answer: v2=v02+2a(x−x0)v^2=v_0^2+2a(x-x_0)
  3. For the same braking deceleration, how does stopping distance change if initial speed doubles?Answer: It becomes four times as large.
  4. A vehicle travels 12 m12\ \text{m} during reaction time and then travels 48 m48\ \text{m} while braking. What is its total stopping distance?Answer: 60 m60\ \text{m}
  5. A car's modeled travel time is measured from t=0t=0. A quadratic calculation gives roots of 8 s8\ \text{s} and −12 s-12\ \text{s}. Which root represents the travel time after the motion begins?Answer: 8 s8\ \text{s}

Based on College Physics 2e by Paul Peter Urone, Roger Hinrichs (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

All General physics lessons