General physicsLesson 6 of 9 in the course Oscillatory Motion and Waves

Circular-Motion Projection: Position, Speed, and Mass–Spring Period

5 flashcards · 5 quiz questions · 5 match pairs · 5 fill-in sentences · English

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Summary

Uniform circular motion provides a useful geometric model for understanding simple harmonic motion (SHM). Imagine a ball rotating at a steady rate on a vertical turntable. Its shadow, projected onto a fixed horizontal axis, moves back and forth in simple harmonic motion.

Consider a point PP traveling around a circle of radius XX at constant angular velocity ω\omega. Its projection onto a fixed axis moves between −X-X and +X+X.

All flashcards

How does uniform circular motion model simple harmonic motion?
The projection of a point moving uniformly around a circle onto a fixed axis moves back and forth in SHM. The circular point travels around the circle, while its projection oscillates along a line.
What do the radius XX and angular velocity ω\omega represent in the projection model?
XX is the amplitude of the projected oscillation, and ω\omega sets how quickly the circular point and its projection move through their cycles.
What are the position and angular-frequency relations for the projection?
For a projection starting at the positive endpoint, x(t)=Xcos⁡(ωt)x(t)=X\cos(\omega t). The angular velocity and period are related by ω=2π/T\omega=2\pi/T.
How does the projection’s speed vary during an oscillation?
Its speed is greatest at the center, where x=0x=0, and zero at the endpoints, where x=±Xx=\pm X. Its magnitude is ∣v∣=vmax⁡1−x2/X2|v|=v_{\max}\sqrt{1-x^2/X^2}.
What is the period of an ideal mass–spring oscillator?
For a mass mm attached to a spring with spring constant kk, the period is T=2πm/kT=2\pi\sqrt{m/k}.

Quiz questions

  1. In the circular-motion model of simple harmonic motion, what does the circle’s radius represent?Answer: The amplitude of the oscillation.
  2. A point completes one revolution around its circle in time TT. How many complete oscillations does its projection make in that time?Answer: One complete oscillation.
  3. Which expression gives the projection’s position when it starts at the positive endpoint at t=0t=0?Answer: x(t)=Xcos⁡(ωt)x(t)=X\cos(\omega t)
  4. At what position does the projection have its greatest speed?Answer: At equilibrium, where x=0x=0.
  5. What is the period of an ideal mass–spring oscillator with mass mm and spring constant kk?Answer: T=2πm/kT=2\pi\sqrt{m/k}

Based on College Physics 2e by Paul Peter Urone, Roger Hinrichs (OpenStax), licensed CC BY 4.0. Adapted into a summary, flashcards and quizzes.

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